10.map filter lambda
Map
map() function is used to execute a function for each item in the iterable.
For a map() function, a specific function to execute and iterable will be sent as parameters.
Syntax
map(function, iterables)
map applies the function to every element of the list.
Example
def square(num):
return(num**2)
my_nums=[1,2,3,4,5]
print(map(square,my_nums)) # provides just address of this output, in order to view we need to convert the output as list.
print(list(map(square,my_nums)))
Result:
<map at 0x7f9a483e9ad0>
[1, 4, 9, 16, 25]
Example
def myfunc(a, b):
return a + b
x = map(myfunc, ('apple', 'banana', 'cherry'), ('orange', 'lemon', 'pineapple'))
print(list(x))
Result:
['appleorange', 'bananalemon', 'cherrypineapple']
Filter
filter() function returns an iterator when the items are filtered through a function and if the function accepts the item.
Syntax
filter(function, iterables)
Example
def check_even(num):
return num%2 == 0
mynums = [1,2,3,4,5,6]
print(filter(check_even,mynums))
print(list(filter(check_even,mynums)))
Result:
<<filter at 0x7fa8a05e6c50>>
[2, 4, 6]
Lambda
Example
def square(num):
return num**2
# The above function can also be written as
def square(num): return num**2
print(square(3))
when we use the function only once, we will define it as lambda.
lambda is nothing is but a simple anonymous function.
Syntax
lambda arguments : expression
lambda function can take any number of arguments, but can only have one expression.
Example
square = lambda num: num**2
square(5)
As lambda is anonymous, we generally won't give any name for it.
We will use lambda expression in map and filter functions as below
Example
list(map(lambda num: num**2, my_nums))
list(filter(lambda num: num%2 == 0, my_nums))
Example
names = ['Andy','Eve','Sally']
print(list(map(lambda name: name[0], names)))
Result:
['A', 'E', 'S']
print(list(map(lambda name: name[::-1], names)))
Result:
['ydnA', 'evE', 'yllaS']
The power of lambda is better shown when we use anonymous function inside another function
Example
def myfunc(n):
return lambda a : a * n
mydoubler = myfunc(2)
print(mydoubler(11))